pinkclover816 pinkclover816

02-06-2021
Mathematics

contestada

Solve for x. Round to the nearest tenth.

Solve for x Round to the nearest tenth class=

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heikepowe1976 heikepowe1976

02-06-2021

Answer:

22.8

Step-by-step explanation:

[tex]a^{2} +b^{2} =c^{2} \\20^{2} +11^{2} =x^{2} \\400+121=x^{2}\\\sqrt{521} =x\\\\or\\\\22.8 = x[/tex]

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