PaxtenI682050 PaxtenI682050

03-11-2022
Mathematics

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question 1A.) 4, 8, 12B.)6, 10, 26C.) 2, 6, 22D.) 1, 2, 6

question 1A 4 8 12B6 10 26C 2 6 22D 1 2 6 class=

Respuesta :

BaironR20043 BaironR20043

03-11-2022

Answer

Option C is correct.

a₁, a₂ and a₃ = 2, 6 and 22 respectively.

Explanation

We have been told that

a₀ = 1

And any term after that is given as

[tex]a_{i+1}=4a_i-2[/tex]

So,

a₁ = 4a₀ - 2

a₁ = 4 (1) - 2

a₁ = 4 - 2

a₁ = 2

a₂ = 4a₁ - 2

a₂ = 4 (2) - 2

a₂ = 8 - 2

a₂ = 6

a₃ = 4a₂ - 2

a₃ = 4 (6) - 2

a₃ = 24 - 2

a₃ = 22

Hope this Helps!!!

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