Respuesta :

anchitthawi

[tex] \frac{10 {x}^{2}y }{x {y}^{2} } = 5y \\ 10 \frac{x}{y} = 5y \\ \frac{10x}{5} = {y}^{2} \\ 2x = {y}^{2} \\ then \: y = \sqrt{2x} \: or \: - \sqrt{2x} [/tex]